Agronomy Degree Practice Exam

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Elevate your agronomy skills with our exam. Prepare using quizzes, flashcards, and multiple choice questions. Familiarize yourself with key concepts and excel in your exam!

Each practice test/flash card set has 50 randomly selected questions from a bank of over 500. You'll get a new set of questions each time!

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To treat 250 acres, how many lbs of Sencor will be required if it is applied at 4 ounces per acre?

62.5 lbs
50 lbs
75 lbs
100 lbs

The correct answer is: 62.5 lbs

To determine the correct amount of Sencor required for treating 250 acres at a rate of 4 ounces per acre, it is essential to perform some calculations first. Start by converting the application rate from ounces to pounds since the answer choices are provided in pounds. There are 16 ounces in a pound, so 4 ounces is equal to 4/16 or 0.25 pounds per acre. Next, calculate the total amount of Sencor needed for 250 acres by multiplying the application rate per acre (0.25 pounds) by the total number of acres (250 acres): 0.25 lbs/acre × 250 acres = 62.5 lbs. Thus, to treat 250 acres at 4 ounces per acre, a total of 62.5 pounds of Sencor is required. This calculation confirms that the correct choice is 62.5 lbs, as it accurately reflects the total quantity needed based on the specified application rate and area.